python修改yaml及properties配置文件
虽然yaml库可以直接读取、修改、生成yaml，但是在yaml的注释兼容保留方便存在一定的问题，个人觉得修改指定行的yaml内容或者setting.properties这类文件，按行读取和识别，还是比较方便的，如下代码分别给出了修改以等号为配置特征的setting.properties的配置文件，以及以：为分隔的yaml配置文件兼容修改的方案。
import yaml
#######修改setting.properties类型的配置文件
@staticmethod
def changeProperties(path, key, value):
with open(path, 'r', encoding='utf-8') as f:
lines = [] # 创建了一个空列表，里面没有元素
for line in f.readlines():
if line != '\n':
lines.append(line)
f.close()
with open(path, 'w', encoding='utf-8') as f:
flag=0
for line in lines:
if key in line:
newline="{0}={1}".format(key, value)
line = newline
f.write('%s\n' % line)
flag=1
else:
f.write('%s' % line)
#####如果结尾没有仍然写入数据
if (flag == 0):
newline = "{0}={1}".format(key, value)
line = newline
f.write('%s\n' % line)
flag = 1
f.close()
######修改yaml文件内容
@staticmethod
def changeYamlConfig(path, key, value):
with open(path, 'r', encoding='utf-8') as f:
lines = [] # 创建了一个空列表，里面没有元素
for line in f.readlines():
if line != '\n':
lines.append(line)
f.close()
with open(path, 'w', encoding='utf-8') as f:
flag = 0
for line in lines:
if key in line and '#' not in line:
leftstr=line.split(":")[0]
newline = "{0}: {1}".format(leftstr, value)
line = newline
f.write('%s\n' % line)
flag = 1
else:
f.write('%s' % line)
f.close()
return flag