((2-1)-1) = 0
(2-(1-1)) = 2

(2*(3-(4*5))) = -34
((2*3)-(4*5)) = -14
((2*(3-4))*5) = -10
(2*((3-4)*5)) = -10
(((2*3)-4)*5) = 10

class Solution(object):
    def diffWaysToCompute(self, input):
        """
        :type input: str
        :rtype: List[int]
        A: (2*3)-4*5
        ((2*3)-4)*5=>1
        (2*3)-(4*5)=>2
        B:
        2*(3-4)*5
        (2*(3-4))*5=>1
        2*((3-4)*5)=>2
        """
        import re
        tokens = re.split('(\D)', input)
        nums = map(int, tokens[::2])
        ops = map({'+': operator.add, '-': operator.sub, '*': operator.mul}.get, tokens[1::2])
        def build(lo, hi):
            if lo == hi:
                return [nums[lo]]
            ans = []
            for i in range(lo, hi):
                for a in build(lo, i):
                    for b in build(i+1, hi):
                        ans.append(ops[i](a, b))    
            return ans
        return build(0, len(ops))