列表包字典的数据结构

要实现按照字典中的某一个键所对应的值进行排序

有两种办法

由小到大排
列表.sort(key=lambda 形参：形参[str键名称])

由大到小排
列表.sort(key=lambda 形参：形参[str键名称], reverse=True)

由小到大排序
新列表 = sorted(列表，key=lambda 形参：形参[str键名称])

由大到小排序
新列表 = sorted(列表，key=lambda 形参：形参[str键名称], reverse = True)

stuDictList = [
    {"name": "张飞", "power": 96, "tellegent": 30},
    {"name": "诸葛亮", "power": 40, "tellegent": 99},
    {"name": "周瑜", "power": 79, "tellegent": 93},
    {"name": "赵云", "power": 97, "tellegent": 86},
]

print("原始的数据\n{}".format(stuDictList))

print("开始按照武力排序,由小到大")
stuDictList.sort(key=lambda stu: stu["power"])
print("排好序后新数据\n{}".format(stuDictList))

print("开始按照智力值排序,由大到小")

def func(ele):
    return ele["tellegent"]

new_list = sorted(stuDictList, key=func, reverse=True)
print("排序结果{}".format(new_list))

效果

C:\Users\python_hui\Anaconda3\python.exe G:/19-前端-第二回/0813/333.py
原始的数据
[{‘name’: ‘张飞’, ‘power’: 96, ‘tellegent’: 30}, {‘name’: ‘诸葛亮’, ‘power’: 40, ‘tellegent’: 99}, {‘name’: ‘周瑜’, ‘power’: 79, ‘tellegent’: 93}, {‘name’: ‘赵云’, ‘power’: 97, ‘tellegent’: 86}]
开始按照武力排序,由小到大
排好序后新数据
[{‘name’: ‘诸葛亮’, ‘power’: 40, ‘tellegent’: 99}, {‘name’: ‘周瑜’, ‘power’: 79, ‘tellegent’: 93}, {‘name’: ‘张飞’, ‘power’: 96, ‘tellegent’: 30}, {‘name’: ‘赵云’, ‘power’: 97, ‘tellegent’: 86}]
开始按照智力值排序,由大到小
排序结果[{‘name’: ‘诸葛亮’, ‘power’: 40, ‘tellegent’: 99}, {‘name’: ‘周瑜’, ‘power’: 79, ‘tellegent’: 93}, {‘name’: ‘赵云’, ‘power’: 97, ‘tellegent’: 86}, {‘name’: ‘张飞’, ‘power’: 96, ‘tellegent’: 30}]

Process finished with exit code 0