N!

Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)
Total Submission(s): 73973    Accepted Submission(s): 21474

Problem Description

Given an integer N(0 ≤ N ≤ 10000), your task is to calculate N!

Input

One N in one line, process to the end of file.

Output

For each N, output N! in one line.

Sample Input

1 2 3

Sample Output

1 2 6

Author

题意：
求n 的阶乘。
思路：
在熟悉下JAVA大数。
直接每一次输入n，循环n次就过了，只不过不能提前打表，跑不出来。。。

import java.util.Scanner;
import java.math.BigInteger;
public class Main {

	public static void main(String[] args) {
		Scanner cin = new Scanner(System.in);
		while(cin.hasNext()){
			int n = cin.nextInt();
			BigInteger a = BigInteger.valueOf(1);
			for (int i = 1; i <= n; ++i){
				BigInteger unit = BigInteger.valueOf(i);
				a = a.multiply(unit);
			}
			System.out.println(a.toString());
		}	
	}
}